Question

verify the identity that picture question

Answer 1

I hope this may help you.....

Answer 2

1.(i) Taking LHS
(a-b)^2 = (3-1)^2 = 2^2 = 4
Taking RHS
a^2 + b^2 - 2ab = 3^2 + 1^2 - 2(3)(1)
= 9+1-6 = 4
Since LHS = RHS
Therefore, (a-b)(a+b) = a^2+b^2-2ab
(ii) Taking LHS
(a-b)^2 = (5-2)^2 = 3^2 = 9
Taking RHS
a^2 + b^2 - 2ab = 5^2 + 2^2 -2(5)(2)
= 25 + 4 - 20 = 9
Since LHS = RHS
Therefore, (a-b)(a+b) = a^2+b^2-2ab
2.(I) Taking LHS
(a+b)(a-b) = (3-2)(3+2) = 1(5) = 5
Taking RHS
a^2 - b^2 = 3^2 - 2^2 = 9-4 = 5
Since RHS=LHS
Therefore, (a+b)(a-b) = a^2 - b^2
(ii) Taking LHS
(a+b)(a-b) = (2+1)(2-1) = 3(1) = 3
Taking RHS
a^2 - b^2 = 2^2 - 1^2 = 4-1 = 3
Since LHS=RHS
Therefore, (a+b)(a-b) = a^2 - b^2
Hence, verified.