Question

Verify the identity (x+a ) (x+b )= x^+(a+b ) x+,ab for na=2,b=3 and x=4 ?​

Answer 1

Answer:

We have

(x + a) (x + b) = x² + (a + b)x + ab X

Putting a = 2, b =3 and x = 4, we have

LHS = (x + a) (x + b)

= (4 + 2) (4 +3)

= 6 x 7

= 42

RHS = x² + (a + b)x + ab = 16+ 5 x 4 + 6

= (4)² + (2+3)x+ (2) x (3)

= 16 +26

= 42

i.e. LHS = RHS

Thus, the given identity is true for the given values.

Step-by-step explanation:

We have

(x + a) (x + b) = x² + (a + b)x + ab X

Putting a = 2, b =3 and x = 4, we have

LHS = (x + a) (x + b)

= (4 + 2) (4 +3)

= 6 x 7

= 42

RHS = x² + (a + b)x + ab = 16+ 5 x 4 + 6

= (4)² + (2+3)x+ (2) x (3)

= 16 +26

= 42

i.e. LHS = RHS

Thus, the given identity is true for the given values.