Verify the identity (x + a)(x - b) = x2 + (a - b)x - ab for a = 2,b=7 x=1
Answers
Answered by
2
Answer:
The proving is given belowside↓↓↓
Step-by-step explanation:
Given that,
a=2, b=7, x=1
LHS=(x+a)(x-b)
Putting the values,
(1+2)(1-7)
=3×(-6)
=(-18)
RHS=x²+(a-b)x-ab
Putting the values,
1²+(2-7)1-2×7
=1+(-5)1-14
=1-5-14
=(-18)
So, LHS=RHS.(proved)
Therefore, (x+a)(x-b)=x²+(a-b)x-ab.
Hope it helps you...
Pls mrk me brainliest...
Similar questions