verify the law of conservation of mass in the given reaction.
-:2 moles of hydrogen gas reacts with one mole of oxygen gas to give 2 moles of water (atomic mass: H=1, O=16)
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2 H2 + O2 —> 2 H2O
Now, molecular mass of H2 = 2g. Therefore, 2 moles of H2 means 2*2=4g H2.
molecular mass of O2 =32. Therefore, 1 mole of O2 means 1*32=32g O2
So by adding the LHS — we get —
4+32=36g
In RHS we have 2*H + 1*O which means—
2*1 + 1*16 = 2+16=18.
Thus, 1 mole of H2O = 18 g
So, 2 moles of water means 2*18=36g.
This LHS=RHS (verified)
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