Question

verify the law of constant proportion for an experiment in which 2.06 g of copper forms 2.576 g of copper oxide and in another experiment 7.344 g of copper oxide reduces to form 5.876 g of copper

Answer 1

Explanation:

Part One:

            2Cu + O₂ ----> 2CuO

         Mole ratio of copper : copper oxide

                                    2      :       2

                              ∴    1       :       1

1 mole of Cu = 64g

1 mole of O = 16g

1 mole of Cu = 64g

∴ Number of moles in 2.06g of Cu = $\frac{2.06}{64}$

                                                         = 0.032 mol

1 mole of CuO = 80g

∴ Number of moles in 2.576g of CuO = $\frac{2.576}{80}$

                                                              = 0.032 mol

This shows that the law of constant proportion is being upheld.

Part Two:

1 mole of Cu = 64g

∴ Number of moles in 5.876g of Cu = $\frac{5.876}{64}$

                                                         = 0.0918 mol

1 mole of CuO = 80g

∴ Number of moles in 7.344g of CuO = $\frac{7.344}{80}$

                                                              = 0.0918 mol

This also shows that the law of constant proportion is being upheld.

                                                                            Hope this helps! :)

                                                                                          - Abby <3

Answer 2

Answer:

Explanation:

Part One:

           2Cu + O₂ ----> 2CuO

        Mole ratio of copper : copper oxide

                                   2      :       2

                             ∴    1       :       1

1 mole of Cu = 64g

1 mole of O = 16g

1 mole of Cu = 64g

∴ Number of moles in 2.06g of Cu =  

                                                        = 0.032 mol

1 mole of CuO = 80g

∴ Number of moles in 2.576g of CuO =  

                                                             = 0.032 mol

This shows that the law of constant proportion is being upheld.

Part Two:

1 mole of Cu = 64g

∴ Number of moles in 5.876g of Cu = 0.0918 mol

1 mole of CuO = 80g

∴ Number of moles in 7.344g of CuO =  0.0918 mol

This also shows that the law of constant proportion is being upheld.