Verify the law of multiple proportions for the following oxides of nitrogen- NO2, NO, NO3, N2O5, N2O
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The ratios mean that for nitrogen monoxide (NO), for every 1 g of nitrogen, there is 1.143 g of oxygen. For nitrogen dioxide (NO2), for every 1 g of nitrogen, there are 2.286 g of oxygen.
How does the law of multiple proportions apply to this? We can demonstrate it by taking the ratios of the oxygen for the two compounds and putting them side by side. Then we divide it by the smaller number, which is 1.143:
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