Question

verify the lhs =rhs class 8 ​

Answer 1

Answer:

this is your answer hope it will help you

Answer 2

In the above question, we need to verify if the given property is true ⇒

$(a-b)\neq (b-a)$

(i)

$a=\frac{1}{6}$

$b=\frac{1}{5}$

$(\frac{1}{6}-\frac{1}{5})\neq (\frac{1}{5}-\frac{1}{6})$

LCM of 6 and 5 is 30

$(\frac{1*5}{6*5}-\frac{1*6}{5*6})\neq (\frac{1*6}{5*6}-\frac{1*5}{6*5})$

$(\frac{5}{30}-\frac{6}{30})\neq (\frac{6}{30}-\frac{5}{30})$

$\frac{-1}{30} \neq \frac{1}{30}$

∴ $\frac{-1}{30} \neq \frac{1}{30}$ and therefore we can conclude that $(a-b)\neq (b-a)$.

(ii)

$a=\frac{3}{5}$

$b=\frac{5}{3}$

$(\frac{3}{5} -\frac{5}{3} )\neq (\frac{5}{3} -\frac{3}{5} )$

LCM of 5 and 3 is 15.

$(\frac{3*3}{5*3} -\frac{5*5}{3*5} )\neq (\frac{5*5}{3*5} -\frac{3*3}{5*3} )$

$(\frac{9}{15} -\frac{25}{15} )\neq (\frac{25}{15} -\frac{9}{15} )$

$\frac{-16}{25} \neq \frac{16}{25}$

∴ $\frac{-16}{25} \neq \frac{16}{25}$ and therefore we can conclude that $(a-b)\neq (b-a)$.