verify the nature of graph of the following pair of linear equations graphically x+y=7
2x+2y=12....
Answers
Answered by
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Step-by-step explanation:
Perimeter of trapezium = 104 m
Length of Non-parallel sides = 18 m and 22 m
Altitude = 16m
Area of Trapezium = 0.5 * (sum of parallel sides)*altitude ------ (1)
Sum of parallel sides = Perimeter - (sum of non-parallel sides) = 104 m - (18+22)m = 104-40 m = 64 m
From (1), Area of Trapezium = 0.5*64*16 = 512 m^2
Ans: Area of trapezium = 512 m^2
Answered by
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Solution:
x + y = 7 ... Eq.1
2x + 2y = 12 ... Eq.2
Simultaneous linear equations using elimination and substitution method.
Convert in the form of slope-intercept
y = mx + b
x + y = 7 ... Eq.1
y = -x + 7
slope m = -1
y-intercept b = 7
2x + 2y = 12 ... Eq.2
2y = -2x + 12
y = -x + 6
slope m = -1
y-intercept b = 7
We get from the graph that two straight lines are parallel to each other.
Therefore, the given system of equations has no solutions.
See the picture graph below to verify the nature of the graph.
Eq.1 (red)
Eq.2 (blue)
x + y = 7 ... Eq.1
2x + 2y = 12 ... Eq.2
Simultaneous linear equations using elimination and substitution method.
Convert in the form of slope-intercept
y = mx + b
x + y = 7 ... Eq.1
y = -x + 7
slope m = -1
y-intercept b = 7
2x + 2y = 12 ... Eq.2
2y = -2x + 12
y = -x + 6
slope m = -1
y-intercept b = 7
We get from the graph that two straight lines are parallel to each other.
Therefore, the given system of equations has no solutions.
See the picture graph below to verify the nature of the graph.
Eq.1 (red)
Eq.2 (blue)
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