verify the number alongside of the cubic polynomial below are their zeroes. Verify the relationship between the zeroes and the co-effeciients in each case: x^3+6x^2- 11x +6; -1,-2,-3
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- given equation is x^3+6x^2-11x+6
- if x=-1 then ,
- (-1)^3+6(-1)^2-11(-1)+6
- -1+6+11+6
- then answer is 22
- if x=-2 then,
- (-2)^3+6(-2)^2-11(-2)+6
- -8+24+22+6
- then answer is 44
- if x=-3 then,
- (-3)^3+6(-3)^2-11(-3)+6
- -27+54+33+6
- then answer is 66
- so -1,-2,-3, are not the zeroes of polynomial x^3+6x^2-11x+6
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