Question

Verify the property ax(b+c)=(axb)+(axc) by taking: 1) a (1/3), b =0, c = (-7/6) 2)
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Answer 1

Step-by-step explanation:

a(b+c)=ab+ac

this is the distributive property

given

a=-10

b=-9

c=8

So L.H.S.

= a(b+c)= -10*(-9+8)=-10*(-1)=10

=> L.H.S =10•••••••••(i)

again R.HS.

= ab+ac = (-10)*(-9)+(-10)*8

=90–80 =10

=> R.HS. =10••••••••••(ii)

from (i)&(ii)

L.H.S=R.H.S=10

hence shown that the distributive property is true for the given numbers.

a(b+c)=(axb)+(axc)

L.H.S=a(b+c)

=-10(-9+8)

=(-10)x(-1)

=10

R.H.S=(axb)+(axc)

=(-10×-9)+(-10×8)

=90–80

=10

Hence proof

L.H.S=R H S