Verify the property: x × (y + z) = x × y + x × z by taking: [4] X = -2/7 , y = 10/13 , z = 5/6
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Answer:
x×(y×z)
=1×(
2
−1
×
4
1
)
=1×(
8
−1
)
=
8
−1
(x×y)×z
=(1×
2
−1
)×
4
1
=
2
−1
×
4
1
=
8
−1
So x×(y×z)=(x×y)z
(b)x×(y×z)=
3
2
×(
7
−3
×
2
1
)
=
3
2
×
14
−3
=
42
−6
(x×y)×z=(
3
2
×
7
−3
)
=
21
−6
×
2
1
=
42
−6
=
2
−6
So, x×(y+z)=(x×y)×z
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