Verify the relation between the zeros and coefficient of a quadratic polynomial (y2-5)
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We can write 5 as (√5)^2=(y)^2-(√5)^2=(y+√5)(y-√5)=>y=+√5,-√5sum of roots = -b/a=>√5-√5 = 0/1 ------(there is no of x so its coffecient is 0)=>0 = 0 LHS=RHSproduct of roots=c/a=>√5 × (-√5) = -5/1=>-5 = -5LHS=RHS
by using (a)^2-(b)^2=(a+b)(a-b)
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