Question

verify the relation between zeroes and coefficient of the quadratic polynomial xsquare-4​

Answer 1

Factorize the equation, we get (x+2)(x−4)

So, the value of x2−2x−8 is zero when x+2=0,x−4=0, i.e., when x=−2 or x=4.

Therefore, the zeros of x2−2x−8 are -2 and 4.

Now,

⇒Sum of zeroes =−2+4=2=−12=−Coefficient  of  x2Coefficient  of  x

⇒Product of zeros =(−2)×(4)=−8 = 1−8=Coefficient  of  x2Constant  term

Answer 2

$\large\underline\mathtt\red{Answer:}$

Find zeroes of the polynomial x^(2)-4 and verify the relation between zeroes and coefficients. ∴ Zeroes of p(x)are 2 and -2. and product of zeroes =(2)(-2)=-4=-41=coefficient termcoefficient ofx2 Hence Verified.