Question

verify the relation between zeros and coefficient of the quadratic polynomial p(x)=X2 -15​

Answer 1

Step-by-step explanation:

Let p(x)=x²−3

Zero of the polynomial is the value of x where p(x)=0

Put p(x)=0⇒x²−3=0

⇒x² − ( √3)²= 0

So,x=√3,−√3

∴α= √3 and β= √−3 are zeroes of the polynomial.

We can write p(x)=x²−3=x 2 +0−3 is of the

form ax²+bx+c where a=1,b=0,c=−3

L.H.S=Sum of the zeroes=α+β= √3 − √3 =0

and R.H.S=Sum of the zeroes

Answer 2

Step-by-step explanation:

x^2-15=0

x^2=15

x=±√15. (Root if equation).

x^2+0X-15. (a=1,b=0,c=15)

√15+ (-√15)=-b/a

√15-√15 = 0/1

0=0

√15×-√15=c/a

15=15/1

15=15

Hence, relation verified

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