Question

Verify the relationship between the zeroes and the coefficients of x square-25
by finding its zeroes

Answer 1

Hey there !!

Ur question is
${x}^{2} - 25 = 0 \\ = > {x}^{2} = 25 \\ = > x = 5 \: or \: - 5$
★Verification ★ -

here
a = 1 , b = 0 , c = -25

$( \alpha + \beta ) = \frac{ - b}{a} \\ = > (5 + ( - 5)) = \frac{0}{1} \\ = > 0 = 0 \\ \\ and \: \\ \alpha \beta = \frac{c}{a} \\ = > 5 \times - 5 = - 25 \div 1 \\ = > - 25 = - 25$
hope this helps u
^_^