Question

Verify the relationship between the zeros and cofficients of the polynomial x2 + 4x-12

Answer 1

Step-by-step explanation:

HEY THERE!!!

Method Of Solution:-

Equation: x²+x -12

Now, Solving this Equation!!

x²+x-12

=> x²+4x-3x -12

=> x(x+4)-3(x+4)

=> (x+4)(x-3)

Now, •°•  f(x) = 0

•°• (x+4)(x-3)

=> x+4=0

°•° => -4

Also, (x-3) = 0

•°• x => 3

Hence, x = -4 or 3

So, The Zeroes f(x) are -4 and 3/2.

Sum of Zeroes = (-4+3) = -1/1 => -(Coefficient of x)/Coefficient of x²

Product of Zeroes = (-4×3) = -12/1 => Constant term/Coefficient of x².

Answer 2

Answer:

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