Question

Verify the relationship between the zeros and the coefficients and find the zeros of the polynomial

p²-17p-60

Answer 1

Answer:

p=20 or -3

Step-by-step explanation:

Let @ and ß be the zeros

Consider f(p) to be the given polynomial.

f(p)=p²-17p-60

We know,

f(p)=0

→p²-17p-60=0

→p²-20p+3p-60=0

→p(p-20)+3(p-20)=0

→(p+3)(p-20)=0

→p+3=0 or, p-20=0

→p=-3 or p=20

→@=20 and ß= -3

Verification:

•Sum of zeros:

@ + ß

=20+(-3)

=17/1

= -x coefficient/x² coefficient

•Product of zeros:

@ß

=20(-3)

= -60/1

= constant term/x² coefficient