Question

verify the relationship between zeroes and coffients of the polynomial x2-4
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Answer 1

Answer :

→ x² - 4 = 0

Here, a = (co efficient of x²) = 1

b = (co efficient of x) = 0

c = (constant term) = -4

→ x² - 4 = 0

(x)² - (2)² = 0 [ a² - b² = (a + b)(a - b) ]

(x + 2)(x - 2) = 0

x = ± 2

→ α = 2 ; β = -2

→ Sum of roots :

α + β = 2 - 2 = 0

→ Product of roots :

αβ = (2)(-2) = -4

Verification :

→ Sum of roots = -b/a

α + β = -0/1

0 = 0

→ Product of roots = c/a

αβ = -4/1

-4 = -4

LHS = RHS

Hence, verified.

Answer 2

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