Question

Verify the relationship between zeros and coefficients of the polynomial √3x2+10x+73






plz explain step by step​

Answer 1

here is your answer may be...

if it is wrong so sorry

Answer 2

Answer:

Given, q(x) = √3x2 + 10x + 7√3

We put q(x) = 0 ⇒

√3x2 + 10x + 7√3 = 0

⇒ √3x2 + 3x + 7x + 7√3x = 0

⇒ √3x(x + √3) + 7 (x + √3) = 0

⇒ (x + √3)(√3x + 7) = 0

This gives us 2 zeros, for

x = -√3 and x = -7/√3

Hence, the zeros of the quadratic equation are -√3 and -7/√3.

Now, for verification

Sum of zeros = – coefficient of x / coefficient of x2

-√3 + (-7/√3) = – (10) /√3

(-3-7)/ √3 = -10/√3

-10/ √3 = -10/√3

Product of roots = constant / coefficient of x2 (-√3) x (-7/√3) = (7√3)/√3

7 = 7

Therefore, the relationship between zeros and their coefficients is verified.