verify the result n(A unionB)=n(A)+n(B)-n(A intersection B)
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♡[Answer]♡
Here from vendiagram
= n(a-b) =n(anb)
And, n(b-a) =n(b)-n(anb)
Again from vendiagram we get 1 formula
= n(aub) =n(a-b)+n(b-a)+n(a-b)
= n(aub) =n(a)+n(b)-n(anb) [putting the value of n(a-b),n(b-a)]
Hence, proved
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