Verify the Rolle’s theorem for the following function f(x)=x^3+5x^2-6x,x(0,1)
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Step-by-step explanation:
Given f(x)=x
2
+5x+6=(x+2)(x+3) on [−3,−2].
Now f(−3)=0=f(−2).
Also the given function is continuous in [−3,−2] since polynomial function is continuous every where and differentiable also. So the given function is also differentiable in (−3,−2).
So the given function satisfies all the conditions for Rolle's theorem in [−3,−2].
I hope it helps you
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