verify the sule: n (AuB) +n (AnB) = n(A) + n (B) for A={1,2,3,5,7, 9, 11, 13) and B={1,2,4,6,8,12,13)
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Answer:
Step-by-step explanation:
Given,
A = {1,2,3,5,7,9,11,13} and B= {1,2,4,6,8,12,13}
n ( A ) = 8 and n ( B ) = 7
(A ∪B) = {1,2,3,5,7,9,11,13} ∪{1,2,4,6,8,12,13} = {1,2,3,4,5,6,7,8,9,11,12,13}
n (A ∪B) = 12
( A ∩B ) = {1,2,3,5,7,9,11,13} ∩{1,2 4,6,8,12,13} = {1,2,13}
n ( A ∩B ) = 3
∴ n ( A ∪B) + n ( A ∩B ) = 12 + 3 = 15
n ( A ) + n ( B ) = 8 + 7 = 15
Hence we proved that n ( A ∪ B ) + n ( A ∩B ) = n ( A ) + n ( B ).
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