Question

verify the zero of the polynomial indicated against them 2y²+5y - 3 at y=-1/2​

Answer 1

$= 2 {y}^{2} + 5y - 3$

$put \: y = \frac{ - 1}{2} \: in \: above$

$= 2( \frac{ - 1}{2} ) ^{2} + 5( \frac{ - 1}{2} ) - 3$

$= 2( \frac{1}{4} ) - \frac{5}{2} - \frac{3}{1}$

$= \frac{2}{4} - \frac{5}{2} - \frac{3}{1}$

$= \frac{2 - 10 - 12}{4}$

$= \frac{ - 20}{4}$

$= - 5$