Verify using laws of exponents
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umachy71:
which one b or c
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solution is given in the picture
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(b)
5^x+1 = (25×5^x)1/5
5^x+1 = (5²×5^x)1/5
5^x+1 = 5^2+x-1
[a^m×a^n = a^m+n
a^m/a^n = a^m-n]
5^x+1 = 5^x+1
LHS = RHS
(c)
(3/5)^x-1 = 3^x × 5/5^x × 3
3^x-1/5^x-1 = 3^x-1 × 5^1-x
3^x-1 × 5^1-x = 3^x-1 × 5^1-x
LHS = RHS
Hope it helps
5^x+1 = (25×5^x)1/5
5^x+1 = (5²×5^x)1/5
5^x+1 = 5^2+x-1
[a^m×a^n = a^m+n
a^m/a^n = a^m-n]
5^x+1 = 5^x+1
LHS = RHS
(c)
(3/5)^x-1 = 3^x × 5/5^x × 3
3^x-1/5^x-1 = 3^x-1 × 5^1-x
3^x-1 × 5^1-x = 3^x-1 × 5^1-x
LHS = RHS
Hope it helps
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