Math, asked by keerthiverma4889, 9 months ago

Verify weather 3, -3 are zeros of polynomial 2x^3-11x^2+17x-6

Answers

Answered by Anonymous
0

Answer:

Place x = 3 in

  2x^3-11x^2+17x-6 = 0

  (2 * 3 ^ 3) - (11 * 3 ^ 2) + (17 * 3) - 6 = 0

  54 - 99 + 51 - 6 = 0

  0 = 0

Hence, x = 3 is the zero of 2x^3-11x^2+17x-6.

Now, place x = -3 in

  2x^3-11x^2+17x-6 = 0

  [2 * (-3 ^ -3)] - [11 * (-3 ^ 2) + (17 * -3) - 6 = 0

  -54  - 99 - 51 - 6 = 0

  -210 not equal to zero

Hence, x = -3 is not the zero of 2x^3-11x^2+17x-6

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