Verify weather 3, -3 are zeros of polynomial 2x^3-11x^2+17x-6
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Answer:
Place x = 3 in
2x^3-11x^2+17x-6 = 0
(2 * 3 ^ 3) - (11 * 3 ^ 2) + (17 * 3) - 6 = 0
54 - 99 + 51 - 6 = 0
0 = 0
Hence, x = 3 is the zero of 2x^3-11x^2+17x-6.
Now, place x = -3 in
2x^3-11x^2+17x-6 = 0
[2 * (-3 ^ -3)] - [11 * (-3 ^ 2) + (17 * -3) - 6 = 0
-54 - 99 - 51 - 6 = 0
-210 not equal to zero
Hence, x = -3 is not the zero of 2x^3-11x^2+17x-6
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