verify weather Y = 1 is zero of P(y) = Y^4 - 3 y^2 + 2 Y + 1
Answers
Answered by
1
Answer:
y4 - 3y2 + 2y + 1 = p(y)
Step-by-step explanation:
4(1) - 3(1)(2) + 2(1) + 1
4-6 +3
-2+3=1
No,1 is not zero of p(y) = y4 - 3y2 + 2y +1.
Answered by
0
Answer:
Step-by-step explanation:
4(1) - 3(1)(2) + 2(1) + 1
4 - 6 + 3
-2 + 3 = 1
No,1 is not zero of p(y) = y4 - 3y2 + 2y +1.
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