Question

verify weather Y = 1 is zero of P(y) = Y^4 - 3 y^2 + 2 Y + 1​

Answer 1

Answer:

y4 - 3y2 + 2y + 1 = p(y)

Step-by-step explanation:

4(1) - 3(1)(2) + 2(1) + 1

4-6 +3

-2+3=1

No,1 is not zero of p(y) = y4 - 3y2 + 2y +1.

Answer 2

Answer:

Step-by-step explanation:

4(1) - 3(1)(2) + 2(1) + 1

4 - 6 + 3

-2 + 3 = 1

No,1 is not zero of p(y) = y4 - 3y2 + 2y +1.