Math, asked by armaansraarmaandeep, 2 months ago

verify weather Y = 1 is zero of P(y) = Y^4 - 3 y^2 + 2 Y + 1​

Answers

Answered by princeparmar298
1

Answer:

y4 - 3y2 + 2y + 1 = p(y)

Step-by-step explanation:

4(1) - 3(1)(2) + 2(1) + 1

4-6 +3

-2+3=1

No,1 is not zero of p(y) = y4 - 3y2 + 2y +1.

Answered by Raunak110
0

Answer:

Step-by-step explanation:

4(1) - 3(1)(2) + 2(1) + 1

4 - 6 + 3

-2 + 3 = 1

No,1 is not zero of p(y) = y4 - 3y2 + 2y +1.

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