verify wheather g(x) is a factor of f(x) 1)f(x)=2x^2+4x+6, g(x)=x+1
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Given polynomial f(x)=x
3
−4x
2
+x+6 the factor of g(x)=x−2
If x-2 is factor then x-2=0 or x=2
Replace x in p(x) by 2 we get
f(x)=x
3
−4x
2
+x+6
f(2)=(2)
3
−4(2)
2
+(2)+6
⇒f(2)=8−16+2+6
⇒f(2)=0
So f(x) is zero by g(x) =x-2 then g(x)=(x-2) is factor of f(x)=x
3
−4x
2
−x+6
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