Verify when x=2 and y=3 then (x+y)³=x³+y³+3x²y+3xy²
Answers
Answered by
8
hello friends...
Question:- we have to Verify (x+y)³=x³+y³+3x²y+3xy²
when x=2 and y=3
Solution:-
put the values x,y in
(x+y)³ = x³+y³+3x²y +3xy²
(2+3)³ = 2³+3³+3×2²×3 +3×2×3²
5³ = 8 +27 + 36 + 54
125 = 125
Hence
verified that
(x+y)³=x³+y³+3x²y+3xy²
%% hope it helps%%
@@ hope you Mark it as a brainlist answer@@
Question:- we have to Verify (x+y)³=x³+y³+3x²y+3xy²
when x=2 and y=3
Solution:-
put the values x,y in
(x+y)³ = x³+y³+3x²y +3xy²
(2+3)³ = 2³+3³+3×2²×3 +3×2×3²
5³ = 8 +27 + 36 + 54
125 = 125
Hence
verified that
(x+y)³=x³+y³+3x²y+3xy²
%% hope it helps%%
@@ hope you Mark it as a brainlist answer@@
Answered by
3
(2+3)^3=2^3+3^3+(3)2^2(3)+3(2)3^2
125=8+27+36+54
125=125
hence given is verified
125=8+27+36+54
125=125
hence given is verified
Similar questions