verify whether -1 is the root of the equation x^2+4x-5=0
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Answer:
putting -1 in place of x
lhs = (-1)^2 +4×(-1) -5
= 1-4-5
= -8
lhs is not equal to rhs therefore -1 is not the root of the equation
Answered by
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Step-by-step explanation:
Put x= -1 in the equation
substitute in the equation x^2+4x-5=0
(-1)^2+4(-1)-5=0
1-4-5=0
-3-5=0
Therefore x=-1 is not the root of the equation.
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