Question

verify whether 2,3 and 1/2 are zeroes of polynomial .p(x)=2xcube3
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Answer 1

Step-by-step explanation:

p(x)=2x²-11x?+17x-6

Put x=2,

p(2)=2(2)8-11(2)2+17(2)-6

=2(8)-11(4)+34-6

=16-44+28

=44-44=0

Put x=3,

P(3)=2(3)°-11(3)2+17(3)-6

=2(27)-11(9)+51-6

=54-99+51-6

=99-99=0

Put x=1/2,

p(1/2)=2(1/2)°-11(1/2)²+17(1/2)-6

=2(1/8)-11(1/4)+17/2-6=2/8-11/4+17/2-6

=1/4-11/4+17/2-6

=(1-11)/4+17/2-6

=-10/4+17/2-6

=(-10+34-24)/4

=(34-34)/4

=0/4

=0

Therefore,2,3 and 1/2 are the zeroes of the given polynomial.

Hence verified

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