Question

verify whether 2 and -3/2 are the roots of the quadratic equation 2x² - x- 6= 0​

Answer 1

Answer:

sum of roots =-b/a

=(4-3)/2

=1/2

product of roots=c/a

=-6/2

=-3

Answer 2

x = 3 is not a root of the given quadratic equation and $x = \frac{-3}{2}$ is a root of the given quadratic equation.

Step-by-step explanation:

We are given the following quadratic equation in the question:

$2x^2 - x- 6= 0$

We have to check whether 2 and $\frac{-3}{2}$ are roots of the equation.

If they are root of the equation, then they satisfy the equation.

Verification:

$x = 3\\2(3)^2 - (3)- 6= 9 \neq 0$

Thus, x = 3 is not a root of the given quadratic equation.

$x = \dfrac{-3}{2}\\\\2(\dfrac{-3}{2})^2 - (\dfrac{-3}{2})- 6= 0$

Thus, $x = \frac{-3}{2}$ is a root of the given quadratic equation.

#LearnMore

Verify whether 1 is root of Quadratic Equation x²+3x-4=0

https://brainly.in/question/13612412