Question

Verify whether 2 and I are zeroes of polynomial x² - 6x+8.​

Answer 1

Given:-

• p(x) = x² - 6x + 8

To Do :-

• Verify whether 2 and 1 are zeroes of polynomial x² - 6x + 8.

Solution:-

We have,

a = 1

b = -6

c = 8

We know that,

Sum of zeroes = -b/a

⇒ 2 + 1 = -(-6)/1

here,

⇒ 3 ≠ 6

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Product of zeroes = c/a

⇒ 2 × 1 = 8/1

here,

⇒ 2 ≠ 8

Which means 2 and 1 are not the zeroes of the polynomial x² - 6x + 8.

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Answer 2

Answer:

Given:-

p(x) = x² - 6x + 8

To Do :-

Verify whether 2 and 1 are zeroes of polynomial x² - 6x + 8.

Solution:-

Comparing given polynomial with the standard form of polynomial i.e. ax² + bx + c.

We get,

a = 1

b = -6

c = 8

We know that,

Sum of zeroes = -b/a

⇒ 2 + 1 = -(-6)/1

here,

⇒ 3 ≠ 6

━━━━━━━━━━

Product of zeroes = c/a

⇒ 2 × 1 = 8/1

here,

⇒ 2 ≠ 8

Which means 2 and 1 are not the zeroes of the polynomial x² - 6x + 8.

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