Question

verify whether 2 and I are zeroes of polynomial x² - 6x+8.​

Answer 1

Given:-

• p(x) = x² - 6x + 8

To Do :-

• Verify whether 2 and 1 are zeroes of polynomial x² - 6x + 8.

Solution:-

We have,

• a = 1
• b = -6
• c = 8

We know that,

Sum of zeroes = -b/a

⇒ 2 + 1 = -(-6)/1

here,

⇒ 3 ≠ 6

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Product of zeroes = c/a

⇒ 2 × 1 = 8/1

here,

⇒ 2 ≠ 8

Which means 2 and 1 are not the zeroes of the polynomial x² - 6x + 8.

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Answer 2

$\huge \rm {\underline{\pink{Añswer}}}$

Let P(x) = x² - 6x + 8

put x = 2

P(2) = (2)² - 6×2 + 8

=> 4 - 12 + 8

=> 0

Now, Put x = 1

P(1) = 1² - 6 × 1 + 8

=> 1 - 6 + 8

=> 3

Hence 2 is the zeroes of polynomial x² - 6x + 8 .

➝ ᴹⁱˢˢ᭄✿Innocent࿐