verify whether -3/2 are zeroes of p(x)=2x^2-x-6
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Answered by
1
Answer:
Yes
Step-by-step explanation:
P(x) = 2(-3/2)^2 - (-3/2) - 6
P(x) = 9/2 + 3/2 - 6
P(x) = 0
Yes, -3/2 are zeroes of p(x) = 2x^2 - x - 6
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