Math, asked by chinnieshwar2006, 6 days ago

verify whether -3/2 are zeroes of p(x)=2x^2-x-6​

Answers

Answered by yeolekarprasad91
1

Answer:

Yes

Step-by-step explanation:

P(x) = 2(-3/2)^2 - (-3/2) - 6

P(x) = 9/2 + 3/2 - 6

P(x) = 0

Yes, -3/2 are zeroes of p(x) = 2x^2 - x - 6

Answered by miasnow2222
0

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