Question

verify whether -3, 2 are zeroes of the polynomial x³-x²+x - 6​

Answer 1

Step-by-step explanation:

1. given x^3-x^2+x-6
2. let x=-3 then,
3. (-3)^3-(-3)^2+(-3)-6=-27-9-9=-55
4. if x=2 then,
5. 2^3-2^2+2-6=8-4+2-6=0
6. so 2 is zero of the polynomial

Answer 2

Answer:

- 3 is not a zero.

2 is a zero.

Step-by-step explanation:

Given : p(x) = x³ - x² + x - 6

• Putting x = - 3.

→ p(- 3) = (- 3)³ - (- 3)² + (- 3) - 6

→ p(- 3) = (- 27) - (9) + (- 3) - 6

• Opening the brackets.

→ p(- 3) = - 27 - 9 - 3 - 6

→ p(- 3) = - 45

The answer is not equal to zero. Hence, - 3 is not a zero of the above polynomial.

• Putting x = 2.

→ p(x) = (2)³ - (2)² + (2) - 6

→ p(x) = (8) - (4) + (2) - 6

• Opening the brackets.

→ p(x) = 8 - 4 + 2 - 6

→ p(x) = 10 - 10

→ p(x) = 0

The answer is equal to zero. Hence, 2 is the zero of the above polynomial.