Question

Verify whether 3,-3 are the zeros of polynomial 2x^3-11x^2+17x-6

Answer 1

Answer:

Place x = 3 in

   2x^3-11x^2+17x-6 = 0

   (2 * 3 ^ 3) - (11 * 3 ^ 2) + (17 * 3) - 6 = 0

   54 - 99 + 51 - 6 = 0

   0 = 0

Hence, x = 3 is the zero of 2x^3-11x^2+17x-6.

Now, place x = -3 in

     2x^3-11x^2+17x-6 = 0

     [2 * (-3 ^ -3)] - [11 * (-3 ^ 2) + (17 * -3) - 6 = 0

     -54  - 99 - 51 - 6 = 0

       -210 not equal to zero

Hence, x = -3 is not the zero of 2x^3-11x^2+17x-6

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