verify whether 65826 is divisible by 2and3
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It is divisible by 2 because 65826 is an even number.
It is also divisible by 3 because the sum of these digits is a factor of 3.
6+5+8+2+6 = 27
27 is a factor of 3.
Hence it is divisible by both 2 and 3.
It is also divisible by 3 because the sum of these digits is a factor of 3.
6+5+8+2+6 = 27
27 is a factor of 3.
Hence it is divisible by both 2 and 3.
Answered by
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here the divisibility of 2 and 3 will be applicable
do we have to see the last digit which is 6 . we will check that is 6 is divisible by 6 then yes it is so 65826 is divisible by 3 and 2.
do we have to see the last digit which is 6 . we will check that is 6 is divisible by 6 then yes it is so 65826 is divisible by 3 and 2.
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