Question

verify whether (8,9,10)triplets are Pythagorean or not using this formula (2m, m^2-1 m^2+1 )

Answer 1

$h { }^{2} = p {}^{2} + b {}^{2} \\ 10 {}^{2} = 9 {}^{2} + 8 {}^{2} \\ 100 = 81 + 64 \\ 100 = 145 \\ \\ so \: they \: are \: not \: pythagorean \: triple$

Answer 2

$\bold{\huge{\underline{Solution:}}}$

let 2m = 8

=> m = 8/2 = 4

Again,

m² - 1

=> (4)² - 1

=> 16 - 1

=> 15

And,

m² + 1

=> (4)² + 1

=> 16 + 1

=> 17

Hence,

we conclude that (8,9,10) are not the Pythagorean triplets.
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$\bold{\huge{\underline{Thank you!!}}}$