Math, asked by padmagrg7, 4 months ago

verify whether associative property is satisfied for addition, subtraction, multiplication and division for the following sets of rational numbers. 1/3, 2/5 and –3/7​

Answers

Answered by rkcomp31
20

Answer:

Step-by-step explanation:

1/3, 2/5 and –3/7​

Let a=1/3, b=2/5 and c=-3/7

Addition

associative for addition

a+(b+c)=(a+b)+c

LHS=1/3+(2/5-3/7)

=1/3+(14-15)/35

=1/3-1/35

=(35-3)/105=32/105

RHS =(1/3+2/5) -3/7

=(5+6)/15-3/7

=11/15-3/7

=(77-45)/105=32/105

So LHS =RHS Verifies

=======================

Subtraction

a-(b-c)

=1/3-(2/5-(-3/7))

=1/3-(2/5+3/7)

=1/3-(14+15)/35

=1/3-29/35=(35-87)/35*3

=-52/105

Now (a-b)-c

=(1/3-2/5)-(-3/7)

=(5-6)/15+3/7

=-1/15+3/7

=(-7+45)/7

=38/7

here a-(b-c) ≠ (a-b)-c

so associative property is not applicable for subtraction

MULTIPLICATION:

a x (b x c)=(a x b) x c  

a x (b x c)

=1/3 *(2/5 x-3/7))

=1/3 x (-6/35)

=-2/35

Now (a x b) x c

=(1/3 x 2/5) x (-3/7)

=2/15 *(-3/7)

=-2/35

Hence LHS=RHS verified

===========================

DIVISION

a ÷ (b÷c)

=1/3 ÷ ( 2/5 ÷(-3/7)

=1/3 ÷ (-14/15)

=1/2 x (-15/14)

=--15/28

Now (a÷ b) ÷ c

=(1/3 ÷ 2/5) ÷ (-3/7)

=1/3*5/2 ÷(-3/7)

=5/6 x(-7/3)

=-35/18

Here

(a÷ b) ÷ c ≠  a÷( b ÷ c )  

So it proves that   associative property is not satisfied for division  

Answered by saritatyagii852
3

Answer:

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Step-by-step explanation:

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