Question

verify whether g (x) is a factor of f (x) i) f (x) =x³-3x²+4x-4,g(x)=x-2​

Answer 1

Use the Factor Theorem to determine whether g(x) is factor of f(x) in each of the following cases:

f(x)=x

3 −4x 2 +x+6,g(x)=x−2

EASY

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ANSWER

Given polynomial f(x)=x 3 −4x 2 +x+6 the fact ofg(x)=x−2

If x-2 is factor then x-2=0 or x=2

Replace x in p(x) by 2 we get

f(x)=x

3 −4x 2 +x+6

f(2)=(2)

3 −4(2)

2 +(2)+6

⇒f(2)=8−16+2+6

⇒f(2)=0

So f(x) is zero by g(x) =x-2 then g(x)=(x-2) is factor of f(x)=x

3 −4x 2−x+6

Answer 2

Step-by-step explanation:

solution:-

=x³-3x²+4x-4

=x=2.

=2×2×2-3×2×2+4×2-4

=8-12+8-4

=16-16

=0