Question

Verify whether on dividing polynomial x^2-5x+3 by x-3 the remainder is zero or not.

please answer it​

Answer 1

Answer:

p(x)=x

3

−3x

2

+5x−3

g(x)=x

2

−2

p(x)÷g(x)

(x

3

−3x

2

+5x−3)÷(x

2

−2)

x

2

−2

x

3

−3x

2

+5x−3

=(x−3)+

(x

2

−2)

(7x−9)

Quotient =(x−3)

Remainder =(7x−9)

Answer 2

Answer:

hence remainder is 3

Step-by-step explanation:

$\frac{ {x}^{2} - 5x + 3 }{ x- 3} \\ x - 3 ) {x}^{2} - 5x + 3(x - 2\\ \: \: {x}^{2} - 3x \\ \: \: \: \: - 2x + 3 \\ - 2x + 6 \\ \: \: \: \: \: - 3$