Question

Verify whether p(x)=x²-1, x=-1 is zero of it.​

Answer 1

Step-by-step explanation:

x ^2 −1=0

⇒x ^2- (1 )^2 =0

⇒(x−1)(x+1)=0(∵a 2 −b2)

=(a−b)(a+b))

⇒(x−1)=0,(x+1)=0

⇒x=1,x=−1

Hence, the zeroes of the polynomial x 2 −1 are 1,−1.

Answer 2

Answer:

Here's ur answer

$p(x) = {x}^{2} - 1 \\ \: \: \: \: \: \: \: \: \: \: \: = (- 1)^{2} - 1 \\ = + 1 - 1\\ \\ = 0$

Therefore p(x)=x²-1= 0

Hope this helps uh

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