Verify whether the following are zeroes of the polynomial, indicated against them.
(i) p(y)=qy+r , y=-r/q
(ii) p(x) = 5x^2-3 , x=3/√5 and -1/√5
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- p(y)=by putting y=-r/q
we get
q×-r/q+r=0
q will cancel
so -r/q is the zeros of the polynomial
2) p(x)= by putting x=3/√5
we get
5×(3/√5)^2-3=9-3=6
so 3/√5 is not the zeros of the polynomial
by putting x=-1/√5
we get
5×(-1/√5)^2-3=1-3=-2
so -1/√5 is not the zeros of the polynomial
hope it helps you ✌✅✅✅
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