Question

Verify whether the following are zeroes of the polynomial. P(x)= 3x² -1, x=(-1/√3,2/√3 )​

Answer 1

Answer:

Only one gets verified i.e., x ° -1/√3

Step-by-step explanation:

Given polynomial,

=> 3x² - 1

Substituting, x = -1/√3

$= > 3( { \frac{ - 1}{ \sqrt{3} } )}^{2} - 1 \\ = > 3( \frac{1}{3} ) - 1 \\ = > 1 - 1 \\ = > 0$

Hence, -1/√3 is a zero of the polynomial.

Also checking for x = 2/√3

$= > 3( { \frac{2}{ \sqrt{3} } }^{2} ) - 1 \\ = > 3( \frac{4}{3} ) - 1 \\ = > 4 - 1 \\ = > 3$

Hence, 2/√3 is not a zero.