Question

verify whether the following are zeroes of the polynomials, indicator against them
$p(x)=3x+1 \: x = \frac{ - 1}{3}$​

Answer 1

${ \bold { \underline{\large{Required \: Answer : - }}}} \:$

${ \bold { \underline{\large{Given : - }}}} \:$

$p(x)\:=\:3x\:+\:1$ $x\:=\: \dfrac{-1}{3}$

${ \bold { \underline{\large{To \: Find : - }}}} \:$

$whether\:following\:are\:the\:zeroes\:of\:the\:polynomial$

$\large\underline{\boxed{\sf{ ⇝So\:let's \:do\:it\::-}}}$

$p(x)\:=\:3x\:+\:1\: ⇝ eq(1) :-$

$\large\tt\underline{Let's \:put\:value\:of\:x\:in\:equation\:1}$

:$\implies$ $3\:×\: \dfrac{(-1)}{3} \: + \: 1$

:$\implies$ $\cancel{3} \: ×\: \dfrac{(-1)}{\cancel{3}}\:+\:1$

:$\implies$ $-1\:+\:1$

:$\implies$ $\cancel{-1}$ $+$ $\cancel{1}$

:$\implies$ $0$

$\large\underline{\boxed{\sf\therefore\:{ p(x)\:=\:0}}}$

$So,\:following\:are\:the\:zeroes\:of\:the\:polynomial$

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Answer 2

$\huge\underline{\bf \orange{To find:}}$

Whether the following are zeroes of the polynomials.

$\huge\underline{\bf \orange{Solution:}}$

p(x) => 3x + 1_________eq 1.

=> 3× -⅓ +1

=> (-1) + 1

=> 1 - 1

=> 0 Ans.