verify whether the following are zeroes p(x) = x^2- 3x + 2 and x = -2 + 1
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Answer:
no
Step-by-step explanation:
putting value (-1)
(-1)^2-3(-1)+2
=+1+3+2=6
6 is not equal to 0 hence it is not the 0 of p(x)....
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