Math, asked by ky570932, 1 month ago

verify whether the following are zeros of the polynomial indicated against them;

p(y)=(y+3)(y-4), y= -3, 4​

Answers

Answered by pankajpandeyakriti
0

Answer:

(iii) p(x)=x2−1:

Put x=1, we get, p(x)=p(1)=(1)2−1=1−1=0. So, x=1 is the zero of the given polynomial p(x).

p(x)p(−1)=(−1)2−1=1−1=0. So, x=−1 is the zero of the given polynomial p(x).

(iv) p(x)=(x+1)(x−2): Put x=−1, we get, p(x)=(−1+1)(−1−2)=0(−3)=0. So, x=−1 is the zero of the given polynomial p(x).

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