Question

Verify whether the following are zeros of tje polynomials indicated against them

p(x)=3(x)+1,x=-1/3

Answer 1

Answer:

p(-1/3)=3(-1/3)+1

3 is cancelled by 3

then

-1 is cancelled by -1

0

Step-by-step explanation:

yes -1/3 is the 0 of the polynomial

Answer 2

Step-by-step explanation:

$given \\ \: \: \: \: \: \: \: \: p(x) = 3(x) + 1 \\ = >p( \frac{ - 1}{3} ) = 3( \frac{ - 1}{3} ) + 1 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = - 1 + 1 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 0 \\ therefore \: \frac{ - 1}{3} \: is \: a \: zero \: of \: the \: \\ given \: polynomial.$