Question

verify whether the line x-3/-4=y-4/-7=z+3/12 lies in the plane 5x-y+z=8​​

Answer 1

Answer:

ANSWER

Let

−4

x−3

=

−7

y−4

=

13

z+3

=k

Now x=−4k+3

y=−7k+4

z=13k−3

Putting these values in equation of plane we get

5(−4k+3)+7k−4+13k−3=8

Hence it satisfies

Also for line it's direction cosines (

r

−4

,

r

−7

,

r

13

)

Normal(5,−1,1)

So L

1

⋅N=−4(5)−1(−7)+13=−20+7+13=0

Hence condition satisfies

Assertion and reason both correct and reason explains assertion