Math, asked by ABHIRAM16, 1 year ago

verify whether the system of given linear equation as in a unique solution or not 2x+3y-7=0 6x+5y-11=0

Answers

Answered by Poorna160403
20
do that for your answer
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Answered by qwwestham
2

The given system of equations has unique solution.

Given,

System of given linear equations:

2x + 3y - 7 = 0,

6x + 5y - 11 = 0.

To find,

Whether the system of given linear equations has unique solution or not.

Solution,

We can see that the given system of linear equations is as follows.

2x + 3y - 7 = 0, and

6x + 5y - 11 = 0.

Now, when a system of linear equations is such that the equations are

a_1x+b_1y+c_1=0,\\a_2x+b_2y+c_2=0.

Then, the above system of equations has

  • A unique solution, if \frac{a_1}{a_2} \neq\frac{b_1}{b_2},
  • No solution, if \frac{a_1}{a_2} =\frac{b_1}{b_2}\neq\frac{c_1}{c_2},
  • Infinitely many solutions, if \frac{a_1}{a_2} =\frac{b_1}{b_2} = \frac{c_1}{c_2}.

Here, we can see that

\frac{a_1}{a_2} =\frac{2}{6}=\frac{1}{3} and

\frac{b_1}{b_2}=\frac{3}{5}

Since \frac{1}{3} \neq \frac{3}{5}

Thus,

\frac{a_1}{a_2} \neq\frac{b_1}{b_2}

⇒ the condition for unique solution is satisfied.

Therefore, the given system of equations has unique solution.

#SPJ3

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